2(9x-37)=41-5x

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Solution for 2(9x-37)=41-5x equation:



2(9x-37)=41-5x
We move all terms to the left:
2(9x-37)-(41-5x)=0
We add all the numbers together, and all the variables
2(9x-37)-(-5x+41)=0
We multiply parentheses
18x-(-5x+41)-74=0
We get rid of parentheses
18x+5x-41-74=0
We add all the numbers together, and all the variables
23x-115=0
We move all terms containing x to the left, all other terms to the right
23x=115
x=115/23
x=5

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