36n2+45n+9=0

Solution for 36n2+45n+9=0 equation:

36n^2+45n+9=0

a = 36; b = 45; c = +9;
Δ = b2-4ac
Δ = 452-4·36·9
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-27}{2*36}=\frac{-72}{72}
=-1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+27}{2*36}=\frac{-18}{72}
=-1/4
$