36=2(1-7b)+4(b+6)

Solution for 36=2(1-7b)+4(b+6) equation:

36=2(1-7b)+4(b+6)

We move all terms to the left:

36-(2(1-7b)+4(b+6))=0

We add all the numbers together, and all the variables

-(2(-7b+1)+4(b+6))+36=0


We calculate terms in parentheses: -(2(-7b+1)+4(b+6)), so:

2(-7b+1)+4(b+6)

We multiply parentheses

-14b+4b+2+24

We add all the numbers together, and all the variables

-10b+26

Back to the equation:

-(-10b+26)


We get rid of parentheses

10b-26+36=0

We add all the numbers together, and all the variables

10b+10=0

We move all terms containing b to the left, all other terms to the right

10b=-10

b=-10/10

b=-1