360=4x(3x+40)

Solution for 360=4x(3x+40) equation:

360=4x(3x+40)

We move all terms to the left:

360-(4x(3x+40))=0


We calculate terms in parentheses: -(4x(3x+40)), so:

4x(3x+40)

We multiply parentheses

12x^2+160x

Back to the equation:

-(12x^2+160x)


We get rid of parentheses

-12x^2-160x+360=0

a = -12; b = -160; c = +360;
Δ = b2-4ac
Δ = -1602-4·(-12)·360
Δ = 42880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{42880}=\sqrt{64*670}=\sqrt{64}*\sqrt{670}=8\sqrt{670}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-8\sqrt{670}}{2*-12}=\frac{160-8\sqrt{670}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+8\sqrt{670}}{2*-12}=\frac{160+8\sqrt{670}}{-24}
$