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12(x-1)-3x=3(3x-4)
We move all terms to the left:
12(x-1)-3x-(3(3x-4))=0
We add all the numbers together, and all the variables
-3x+12(x-1)-(3(3x-4))=0
We multiply parentheses
-3x+12x-(3(3x-4))-12=0
We calculate terms in parentheses: -(3(3x-4)), so:We add all the numbers together, and all the variables
3(3x-4)
We multiply parentheses
9x-12
Back to the equation:
-(9x-12)
9x-(9x-12)-12=0
We get rid of parentheses
9x-9x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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