360=(35x2+2x)

Solution for 360=(35x2+2x) equation:

360=(35x^2+2x)

We move all terms to the left:

360-((35x^2+2x))=0


We calculate terms in parentheses: -((35x^2+2x)), so:

(35x^2+2x)

We get rid of parentheses

35x^2+2x

Back to the equation:

-(35x^2+2x)


We get rid of parentheses

-35x^2-2x+360=0

a = -35; b = -2; c = +360;
Δ = b2-4ac
Δ = -22-4·(-35)·360
Δ = 50404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50404}=\sqrt{4*12601}=\sqrt{4}*\sqrt{12601}=2\sqrt{12601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{12601}}{2*-35}=\frac{2-2\sqrt{12601}}{-70}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{12601}}{2*-35}=\frac{2+2\sqrt{12601}}{-70}
$