360=(30x2)+0.5x

Solution for 360=(30x2)+0.5x equation:

360=(30x^2)+0.5x

We move all terms to the left:

360-((30x^2)+0.5x)=0

We get rid of parentheses

-30x^2-0.5x+360=0

a = -30; b = -0.5; c = +360;
Δ = b2-4ac
Δ = -0.52-4·(-30)·360
Δ = 43200.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{43200.25}}{2*-30}=\frac{0.5-\sqrt{43200.25}}{-60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{43200.25}}{2*-30}=\frac{0.5+\sqrt{43200.25}}{-60}
$