/7x-10x+18+2x=-5

Solution for /7x-10x+18+2x=-5 equation:

/7x-10x+18+2x=-5

We move all terms to the left:

/7x-10x+18+2x-(-5)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R


We add all the numbers together, and all the variables

-8x+/7x+23=0

We multiply all the terms by the denominator


-8x*7x+23*7x+=0

We add all the numbers together, and all the variables

-8x*7x+23*7x=0

Wy multiply elements

-56x^2+161x=0

a = -56; b = 161; c = 0;
Δ = b2-4ac
Δ = 1612-4·(-56)·0
Δ = 25921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25921}=161$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(161)-161}{2*-56}=\frac{-322}{-112}
=2+7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(161)+161}{2*-56}=\frac{0}{-112}
=0
$