36/(3-4a)-7=5

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Solution for 36/(3-4a)-7=5 equation: 


D( a )

3-(4*a) = 0

3-(4*a) = 0

3-(4*a) = 0

3-4*a = 0

3-4*a = 0 // - 3

-4*a = -3 // : -4

a = -3/(-4)

a = 3/4

a in (-oo:3/4) U (3/4:+oo)

36/(3-(4*a))-7 = 5 // - 5

36/(3-(4*a))-7-5 = 0

36/(3-4*a)-7-5 = 0

36/(3-4*a)+(-7*(3-4*a))/(3-4*a)+(-5*(3-4*a))/(3-4*a) = 0

36-7*(3-4*a)-5*(3-4*a) = 0

28*a+20*a-15+15 = 0

48*a = 0

(48*a)/(3-4*a) = 0

(48*a)/(3-4*a) = 0 // * 3-4*a

48*a = 0

48*a = 0 // : 48

a = 0

a = 0

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