-16/(6a-10)

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Solution for -16/(6a-10) equation: 


D( a )

6*a-10 = 0

6*a-10 = 0

6*a-10 = 0

6*a-10 = 0 // + 10

6*a = 10 // : 6

a = 10/6

a = 5/3

a in (-oo:5/3) U (5/3:+oo)

-16/(6*a-10) = 0

a belongs to the empty set

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