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35z^2+84z+49=0
a = 35; b = 84; c = +49;
Δ = b2-4ac
Δ = 842-4·35·49
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-14}{2*35}=\frac{-98}{70} =-1+2/5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+14}{2*35}=\frac{-70}{70} =-1 $
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