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9v^2-44v=0
a = 9; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·9·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*9}=\frac{0}{18} =0 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*9}=\frac{88}{18} =4+8/9 $
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