35x-7(4x+5)=(4x+22)-3(3x+11)

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Solution for 35x-7(4x+5)=(4x+22)-3(3x+11) equation: 



35x-7(4x+5)=(4x+22)-3(3x+11)

We move all terms to the left:

35x-7(4x+5)-((4x+22)-3(3x+11))=0

We multiply parentheses

35x-28x-((4x+22)-3(3x+11))-35=0



We calculate terms in parentheses: -((4x+22)-3(3x+11)), so:

(4x+22)-3(3x+11)

We multiply parentheses

(4x+22)-9x-33

We get rid of parentheses

4x-9x+22-33

We add all the numbers together, and all the variables

-5x-11

Back to the equation:

-(-5x-11)



We add all the numbers together, and all the variables

7x-(-5x-11)-35=0

We get rid of parentheses

7x+5x+11-35=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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