4+2/5y=20

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Solution for 4+2/5y=20 equation: 



4+2/5y=20

We move all terms to the left:

4+2/5y-(20)=0



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



We add all the numbers together, and all the variables

2/5y-16=0

We multiply all the terms by the denominator


-16*5y+2=0

Wy multiply elements

-80y+2=0

We move all terms containing y to the left, all other terms to the right

-80y=-2

y=-2/-80

y=1/40

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