35=5(4v+7)

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Solution for 35=5(4v+7) equation: 



35=5(4v+7)

We move all terms to the left:

35-(5(4v+7))=0



We calculate terms in parentheses: -(5(4v+7)), so:

5(4v+7)

We multiply parentheses

20v+35

Back to the equation:

-(20v+35)



We get rid of parentheses

-20v-35+35=0

We add all the numbers together, and all the variables

-20v=0

v=0/-20

v=0

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