2(3r+5)-20=3(4r+6)-2r

Solution for 2(3r+5)-20=3(4r+6)-2r equation:

2(3r+5)-20=3(4r+6)-2r

We move all terms to the left:

2(3r+5)-20-(3(4r+6)-2r)=0

We multiply parentheses

6r-(3(4r+6)-2r)+10-20=0


We calculate terms in parentheses: -(3(4r+6)-2r), so:

3(4r+6)-2r

We add all the numbers together, and all the variables

-2r+3(4r+6)

We multiply parentheses

-2r+12r+18

We add all the numbers together, and all the variables

10r+18

Back to the equation:

-(10r+18)


We add all the numbers together, and all the variables

6r-(10r+18)-10=0

We get rid of parentheses

6r-10r-18-10=0

We add all the numbers together, and all the variables

-4r-28=0

We move all terms containing r to the left, all other terms to the right

-4r=28

r=28/-4

r=-7