35=2(1+3x)-3(4-3x)

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Solution for 35=2(1+3x)-3(4-3x) equation: 



35=2(1+3x)-3(4-3x)

We move all terms to the left:

35-(2(1+3x)-3(4-3x))=0

We add all the numbers together, and all the variables

-(2(3x+1)-3(-3x+4))+35=0



We calculate terms in parentheses: -(2(3x+1)-3(-3x+4)), so:

2(3x+1)-3(-3x+4)

We multiply parentheses

6x+9x+2-12

We add all the numbers together, and all the variables

15x-10

Back to the equation:

-(15x-10)



We get rid of parentheses

-15x+10+35=0

We add all the numbers together, and all the variables

-15x+45=0

We move all terms containing x to the left, all other terms to the right

-15x=-45

x=-45/-15

x=+3

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