4(v+5)=-3(2v-6)+4v

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Solution for 4(v+5)=-3(2v-6)+4v equation: 



4(v+5)=-3(2v-6)+4v

We move all terms to the left:

4(v+5)-(-3(2v-6)+4v)=0

We multiply parentheses

4v-(-3(2v-6)+4v)+20=0



We calculate terms in parentheses: -(-3(2v-6)+4v), so:

-3(2v-6)+4v

We add all the numbers together, and all the variables

4v-3(2v-6)

We multiply parentheses

4v-6v+18

We add all the numbers together, and all the variables

-2v+18

Back to the equation:

-(-2v+18)



We get rid of parentheses

4v+2v-18+20=0

We add all the numbers together, and all the variables

6v+2=0

We move all terms containing v to the left, all other terms to the right

6v=-2

v=-2/6

v=-1/3

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