35=1/2(7)(6+b)

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Solution for 35=1/2(7)(6+b) equation: 



35=1/2(7)(6+b)

We move all terms to the left:

35-(1/2(7)(6+b))=0



Domain of the equation: 27(6+b))!=0

b∈R



We add all the numbers together, and all the variables

-(1/27(b+6))+35=0

We multiply all the terms by the denominator


-(1+35*27(b+6))=0



We calculate terms in parentheses: -(1+35*27(b+6)), so:

1+35*27(b+6)

determiningTheFunctionDomain
35*27(b+6)+1

Wy multiply elements

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Back to the equation:

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