12x-4(x-1)=6(x+1)-3

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Solution for 12x-4(x-1)=6(x+1)-3 equation: 



12x-4(x-1)=6(x+1)-3

We move all terms to the left:

12x-4(x-1)-(6(x+1)-3)=0

We multiply parentheses

12x-4x-(6(x+1)-3)+4=0



We calculate terms in parentheses: -(6(x+1)-3), so:

6(x+1)-3

We multiply parentheses

6x+6-3

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

8x-(6x+3)+4=0

We get rid of parentheses

8x-6x-3+4=0

We add all the numbers together, and all the variables

2x+1=0

We move all terms containing x to the left, all other terms to the right

2x=-1

x=-1/2

x=-1/2

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