35=-7(4y+3)

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Solution for 35=-7(4y+3) equation: 



35=-7(4y+3)

We move all terms to the left:

35-(-7(4y+3))=0



We calculate terms in parentheses: -(-7(4y+3)), so:

-7(4y+3)

We multiply parentheses

-28y-21

Back to the equation:

-(-28y-21)



We get rid of parentheses

28y+21+35=0

We add all the numbers together, and all the variables

28y+56=0

We move all terms containing y to the left, all other terms to the right

28y=-56

y=-56/28

y=-2

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