4(3y+12)+5y=-3

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Solution for 4(3y+12)+5y=-3 equation: 



4(3y+12)+5y=-3

We move all terms to the left:

4(3y+12)+5y-(-3)=0

We add all the numbers together, and all the variables

5y+4(3y+12)+3=0

We multiply parentheses

5y+12y+48+3=0

We add all the numbers together, and all the variables

17y+51=0

We move all terms containing y to the left, all other terms to the right

17y=-51

y=-51/17

y=-3

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