35=((x-14)(x-5))/(2)

Solution for 35=((x-14)(x-5))/(2) equation:

35=((x-14)(x-5))/(2)

We move all terms to the left:

35-(((x-14)(x-5))/(2))=0

We multiply parentheses ..

-(((+x^2-5x-14x+70))/2)+35=0

We multiply all the terms by the denominator


-(((+x^2-5x-14x+70))+35*2)=0


We calculate terms in parentheses: -(((+x^2-5x-14x+70))+35*2), so:

((+x^2-5x-14x+70))+35*2

We add all the numbers together, and all the variables

((+x^2-5x-14x+70))+70


We calculate terms in parentheses: +((+x^2-5x-14x+70)), so:

(+x^2-5x-14x+70)

We get rid of parentheses

x^2-5x-14x+70

We add all the numbers together, and all the variables

x^2-19x+70

Back to the equation:

+(x^2-19x+70)


We get rid of parentheses

x^2-19x+70+70

We add all the numbers together, and all the variables

x^2-19x+140

Back to the equation:

-(x^2-19x+140)


We get rid of parentheses

-x^2+19x-140=0

We add all the numbers together, and all the variables

-1x^2+19x-140=0

a = -1; b = 19; c = -140;
Δ = b2-4ac
Δ = 192-4·(-1)·(-140)
Δ = -199
Delta is less than zero, so there is no solution for the equation