-3(5v-7)+9v=9+2(6v-2)

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Solution for -3(5v-7)+9v=9+2(6v-2) equation:



-3(5v-7)+9v=9+2(6v-2)
We move all terms to the left:
-3(5v-7)+9v-(9+2(6v-2))=0
We add all the numbers together, and all the variables
9v-3(5v-7)-(9+2(6v-2))=0
We multiply parentheses
9v-15v-(9+2(6v-2))+21=0
We calculate terms in parentheses: -(9+2(6v-2)), so:
9+2(6v-2)
determiningTheFunctionDomain 2(6v-2)+9
We multiply parentheses
12v-4+9
We add all the numbers together, and all the variables
12v+5
Back to the equation:
-(12v+5)
We add all the numbers together, and all the variables
-6v-(12v+5)+21=0
We get rid of parentheses
-6v-12v-5+21=0
We add all the numbers together, and all the variables
-18v+16=0
We move all terms containing v to the left, all other terms to the right
-18v=-16
v=-16/-18
v=8/9

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