3(c-1)+2(3c+2)=-(3c+1)

Solution for 3(c-1)+2(3c+2)=-(3c+1) equation:

3(c-1)+2(3c+2)=-(3c+1)

We move all terms to the left:

3(c-1)+2(3c+2)-(-(3c+1))=0

We multiply parentheses

3c+6c-(-(3c+1))-3+4=0


We calculate terms in parentheses: -(-(3c+1)), so:

-(3c+1)

We get rid of parentheses

-3c-1

Back to the equation:

-(-3c-1)


We add all the numbers together, and all the variables

9c-(-3c-1)+1=0

We get rid of parentheses

9c+3c+1+1=0

We add all the numbers together, and all the variables

12c+2=0

We move all terms containing c to the left, all other terms to the right

12c=-2

c=-2/12

c=-1/6