35/40x+25=40x

Solution for 35/40x+25=40x equation:

35/40x+25=40x

We move all terms to the left:

35/40x+25-(40x)=0


Domain of the equation: 40x!=0

x!=0/40

x!=0

x∈R


We add all the numbers together, and all the variables

-40x+35/40x+25=0

We multiply all the terms by the denominator


-40x*40x+25*40x+35=0

Wy multiply elements

-1600x^2+1000x+35=0

a = -1600; b = 1000; c = +35;
Δ = b2-4ac
Δ = 10002-4·(-1600)·35
Δ = 1224000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1224000}=\sqrt{14400*85}=\sqrt{14400}*\sqrt{85}=120\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-120\sqrt{85}}{2*-1600}=\frac{-1000-120\sqrt{85}}{-3200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+120\sqrt{85}}{2*-1600}=\frac{-1000+120\sqrt{85}}{-3200}
$