(1-x)+3x=2(x+2)

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Solution for (1-x)+3x=2(x+2) equation: 



(1-x)+3x=2(x+2)

We move all terms to the left:

(1-x)+3x-(2(x+2))=0

We add all the numbers together, and all the variables

(-1x+1)+3x-(2(x+2))=0

We add all the numbers together, and all the variables

3x+(-1x+1)-(2(x+2))=0

We get rid of parentheses

3x-1x-(2(x+2))+1=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

2x-(2x+4)+1=0

We get rid of parentheses

2x-2x-4+1=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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