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35-7x=-x(x+5)
We move all terms to the left:
35-7x-(-x(x+5))=0
We calculate terms in parentheses: -(-x(x+5)), so:We get rid of parentheses
-x(x+5)
We multiply parentheses
-x^2-5x
We add all the numbers together, and all the variables
-1x^2-5x
Back to the equation:
-(-1x^2-5x)
1x^2+5x-7x+35=0
We add all the numbers together, and all the variables
x^2-2x+35=0
a = 1; b = -2; c = +35;
Δ = b2-4ac
Δ = -22-4·1·35
Δ = -136
Delta is less than zero, so there is no solution for the equation
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