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4(n+3)+12+n=3(n-2)+6
We move all terms to the left:
4(n+3)+12+n-(3(n-2)+6)=0
We add all the numbers together, and all the variables
n+4(n+3)-(3(n-2)+6)+12=0
We multiply parentheses
n+4n-(3(n-2)+6)+12+12=0
We calculate terms in parentheses: -(3(n-2)+6), so:We add all the numbers together, and all the variables
3(n-2)+6
We multiply parentheses
3n-6+6
We add all the numbers together, and all the variables
3n
Back to the equation:
-(3n)
2n+24=0
We move all terms containing n to the left, all other terms to the right
2n=-24
n=-24/2
n=-12
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