35(3x-7)=40(2x+2)

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Solution for 35(3x-7)=40(2x+2) equation: 



35(3x-7)=40(2x+2)

We move all terms to the left:

35(3x-7)-(40(2x+2))=0

We multiply parentheses

105x-(40(2x+2))-245=0



We calculate terms in parentheses: -(40(2x+2)), so:

40(2x+2)

We multiply parentheses

80x+80

Back to the equation:

-(80x+80)



We get rid of parentheses

105x-80x-80-245=0

We add all the numbers together, and all the variables

25x-325=0

We move all terms containing x to the left, all other terms to the right

25x=325

x=325/25

x=13

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