34x+95=3(1/4x+9)

Solution for 34x+95=3(1/4x+9) equation:

34x+95=3(1/4x+9)

We move all terms to the left:

34x+95-(3(1/4x+9))=0


Domain of the equation: 4x+9))!=0

x∈R


We multiply all the terms by the denominator


34x*4x+95*4x+9))-(3(1+9))=0

We add all the numbers together, and all the variables

34x*4x+95*4x+9))-(310)=0

We add all the numbers together, and all the variables

34x*4x+95*4x=0

Wy multiply elements

136x^2+380x=0

a = 136; b = 380; c = 0;
Δ = b2-4ac
Δ = 3802-4·136·0
Δ = 144400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144400}=380$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(380)-380}{2*136}=\frac{-760}{272}
=-2+27/34
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(380)+380}{2*136}=\frac{0}{272}
=0
$