5x-2=3(x-4)-2(7-2x)

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Solution for 5x-2=3(x-4)-2(7-2x) equation: 



5x-2=3(x-4)-2(7-2x)

We move all terms to the left:

5x-2-(3(x-4)-2(7-2x))=0

We add all the numbers together, and all the variables

5x-(3(x-4)-2(-2x+7))-2=0



We calculate terms in parentheses: -(3(x-4)-2(-2x+7)), so:

3(x-4)-2(-2x+7)

We multiply parentheses

3x+4x-12-14

We add all the numbers together, and all the variables

7x-26

Back to the equation:

-(7x-26)



We get rid of parentheses

5x-7x+26-2=0

We add all the numbers together, and all the variables

-2x+24=0

We move all terms containing x to the left, all other terms to the right

-2x=-24

x=-24/-2

x=+12

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