34+-1(3c+4)=2(c+3)+c

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Solution for 34+-1(3c+4)=2(c+3)+c equation: 



34+-1(3c+4)=2(c+3)+c

We move all terms to the left:

34+-1(3c+4)-(2(c+3)+c)=0

We add all the numbers together, and all the variables

-1(3c+4)-(2(c+3)+c)=0



We calculate terms in parentheses: -(2(c+3)+c), so:

2(c+3)+c

We add all the numbers together, and all the variables

c+2(c+3)

We multiply parentheses

c+2c+6

We add all the numbers together, and all the variables

3c+6

Back to the equation:

-(3c+6)



We get rid of parentheses

-1(3c+4)-3c-6=0

We add all the numbers together, and all the variables

-3c-1(3c+4)-6=0

We move all terms containing c to the left, all other terms to the right

-3c-1(3c+4)=6

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