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7(5-x)=3(x-5)1
We move all terms to the left:
7(5-x)-(3(x-5)1)=0
We add all the numbers together, and all the variables
7(-1x+5)-(3(x-5)1)=0
We multiply parentheses
-7x-(3(x-5)1)+35=0
We calculate terms in parentheses: -(3(x-5)1), so:We get rid of parentheses
3(x-5)1
We multiply parentheses
3x-15
Back to the equation:
-(3x-15)
-7x-3x+15+35=0
We add all the numbers together, and all the variables
-10x+50=0
We move all terms containing x to the left, all other terms to the right
-10x=-50
x=-50/-10
x=+5
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