33y=4+(8y-6)

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Solution for 33y=4+(8y-6) equation: 



33y=4+(8y-6)

We move all terms to the left:

33y-(4+(8y-6))=0



We calculate terms in parentheses: -(4+(8y-6)), so:

4+(8y-6)

determiningTheFunctionDomain
(8y-6)+4

We get rid of parentheses

8y-6+4

We add all the numbers together, and all the variables

8y-2

Back to the equation:

-(8y-2)



We get rid of parentheses

33y-8y+2=0

We add all the numbers together, and all the variables

25y+2=0

We move all terms containing y to the left, all other terms to the right

25y=-2

y=-2/25

y=-2/25

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