33x=2(33+11x+3x)

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Solution for 33x=2(33+11x+3x) equation: 



33x=2(33+11x+3x)

We move all terms to the left:

33x-(2(33+11x+3x))=0

We add all the numbers together, and all the variables

33x-(2(14x+33))=0



We calculate terms in parentheses: -(2(14x+33)), so:

2(14x+33)

We multiply parentheses

28x+66

Back to the equation:

-(28x+66)



We get rid of parentheses

33x-28x-66=0

We add all the numbers together, and all the variables

5x-66=0

We move all terms containing x to the left, all other terms to the right

5x=66

x=66/5

x=13+1/5

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