(4x+12)/7=(x+3)2

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Solution for (4x+12)/7=(x+3)2 equation: 



(4x+12)/7=(x+3)2

We move all terms to the left:

(4x+12)/7-((x+3)2)=0

We multiply all the terms by the denominator


(4x+12)-(((x+3)2))*7=0

We get rid of parentheses

4x-(((x+3)2))*7+12=0

We move all terms containing x to the left, all other terms to the right

4x-(((x+3)2))*7=-12

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