33=9+3(z+12)

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Solution for 33=9+3(z+12) equation: 



33=9+3(z+12)

We move all terms to the left:

33-(9+3(z+12))=0



We calculate terms in parentheses: -(9+3(z+12)), so:

9+3(z+12)

determiningTheFunctionDomain
3(z+12)+9

We multiply parentheses

3z+36+9

We add all the numbers together, and all the variables

3z+45

Back to the equation:

-(3z+45)



We get rid of parentheses

-3z-45+33=0

We add all the numbers together, and all the variables

-3z-12=0

We move all terms containing z to the left, all other terms to the right

-3z=12

z=12/-3

z=-4

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