2(6n+1)=4(n-5)-2

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Solution for 2(6n+1)=4(n-5)-2 equation: 



2(6n+1)=4(n-5)-2

We move all terms to the left:

2(6n+1)-(4(n-5)-2)=0

We multiply parentheses

12n-(4(n-5)-2)+2=0



We calculate terms in parentheses: -(4(n-5)-2), so:

4(n-5)-2

We multiply parentheses

4n-20-2

We add all the numbers together, and all the variables

4n-22

Back to the equation:

-(4n-22)



We get rid of parentheses

12n-4n+22+2=0

We add all the numbers together, and all the variables

8n+24=0

We move all terms containing n to the left, all other terms to the right

8n=-24

n=-24/8

n=-3

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