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33=3/5(x-2)
We move all terms to the left:
33-(3/5(x-2))=0
Domain of the equation: 5(x-2))!=0We multiply all the terms by the denominator
x∈R
-(3+33*5(x-2))=0
We calculate terms in parentheses: -(3+33*5(x-2)), so:
3+33*5(x-2)
determiningTheFunctionDomain 33*5(x-2)+3
Wy multiply elements
165x(x+3
Back to the equation:
-(165x(x+3)
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