1/4(b-40=20-2b-12

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Solution for 1/4(b-40=20-2b-12 equation: 



1/4(b-40=20-2b-12

We move all terms to the left:

1/4(b-40-(20-2b-12)=0



Domain of the equation: 4(b-40-(20-2b-12)!=0

b∈R



We add all the numbers together, and all the variables

1/4(b-40-(-2b+8)=0

We multiply all the terms by the denominator


1!=0

There is no solution for this equation

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