33=3(u+3)-7u

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Solution for 33=3(u+3)-7u equation: 



33=3(u+3)-7u

We move all terms to the left:

33-(3(u+3)-7u)=0



We calculate terms in parentheses: -(3(u+3)-7u), so:

3(u+3)-7u

We add all the numbers together, and all the variables

-7u+3(u+3)

We multiply parentheses

-7u+3u+9

We add all the numbers together, and all the variables

-4u+9

Back to the equation:

-(-4u+9)



We get rid of parentheses

4u-9+33=0

We add all the numbers together, and all the variables

4u+24=0

We move all terms containing u to the left, all other terms to the right

4u=-24

u=-24/4

u=-6

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