-1/4(-40x+24)+3x=2(8x+9)-3x

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Solution for -1/4(-40x+24)+3x=2(8x+9)-3x equation: 



-1/4(-40x+24)+3x=2(8x+9)-3x

We move all terms to the left:

-1/4(-40x+24)+3x-(2(8x+9)-3x)=0



Domain of the equation: 4(-40x+24)!=0

x∈R



We add all the numbers together, and all the variables

3x-1/4(-40x+24)-(2(8x+9)-3x)=0

We multiply all the terms by the denominator


3x*4(-40x+24)-((2(8x+9)-3x))*4(-40x+24)-1=0



We calculate terms in parentheses: -((2(8x+9)-3x))*4(-40x+24), so:

(2(8x+9)-3x))*4(-40x+24

We add all the numbers together, and all the variables

-40x+(2(8x+9)-3x))*4(+24

Back to the equation:

-(-40x+(2(8x+9)-3x))*4(+24)



We add all the numbers together, and all the variables

3x*4(-40x+24)-(-40x+(2(8x+9)-3x))*424-1=0

Wy multiply elements

12x^2(--(-40x+(2(8x+9)-3x))*424-1=0

We use the square of the difference formula

12x^2(+(-40x+(2(8x+9)-3x))*424-1=0

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