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33.5x^2+36=180
We move all terms to the left:
33.5x^2+36-(180)=0
We add all the numbers together, and all the variables
33.5x^2-144=0
a = 33.5; b = 0; c = -144;
Δ = b2-4ac
Δ = 02-4·33.5·(-144)
Δ = 19296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19296}=\sqrt{144*134}=\sqrt{144}*\sqrt{134}=12\sqrt{134}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{134}}{2*33.5}=\frac{0-12\sqrt{134}}{67} =-\frac{12\sqrt{134}}{67} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{134}}{2*33.5}=\frac{0+12\sqrt{134}}{67} =\frac{12\sqrt{134}}{67} $
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