(3x-8)+(4x)=8x-16

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Solution for (3x-8)+(4x)=8x-16 equation: 



(3x-8)+(4x)=8x-16

We move all terms to the left:

(3x-8)+(4x)-(8x-16)=0

We add all the numbers together, and all the variables

4x+(3x-8)-(8x-16)=0

We get rid of parentheses

4x+3x-8x-8+16=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8

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