32y+6(3y)=27

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Solution for 32y+6(3y)=27 equation: 



32y+6(3y)=27

We move all terms to the left:

32y+6(3y)-(27)=0

We add all the numbers together, and all the variables

95y-27=0

We move all terms containing y to the left, all other terms to the right

95y=27

y=27/95

y=27/95

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