3a(2a+1)+2(a+4)=6a2+3a+2a+8

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Solution for 3a(2a+1)+2(a+4)=6a2+3a+2a+8 equation: 



3a(2a+1)+2(a+4)=6a^2+3a+2a+8

We move all terms to the left:

3a(2a+1)+2(a+4)-(6a^2+3a+2a+8)=0

We multiply parentheses

6a^2+3a+2a-(6a^2+3a+2a+8)+8=0

We get rid of parentheses

6a^2-6a^2+3a+2a-3a-2a-8+8=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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