32x2+50=80x

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Solution for 32x2+50=80x equation: 



32x^2+50=80x

We move all terms to the left:

32x^2+50-(80x)=0

a = 32; b = -80; c = +50;
Δ = b2-4ac
Δ = -802-4·32·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{80}{64}=1+1/4$

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