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(6x-5)(4x+3)=3x(8x+11
We move all terms to the left:
(6x-5)(4x+3)-(3x(8x+11)=0
We multiply parentheses ..
(+24x^2+18x-20x-15)-(3x(8x+11)=0
We calculate terms in parentheses: -(3x(8x+11), so:We get rid of parentheses
3x(8x+11
24x^2+18x-20x-(3x(8x+11)-15=0
We add all the numbers together, and all the variables
24x^2-2x-(3x(8x+11)-15=0
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