32x2+13x-7=52x2+13x-7

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Solution for 32x2+13x-7=52x2+13x-7 equation: 



32x^2+13x-7=52x^2+13x-7

We move all terms to the left:

32x^2+13x-7-(52x^2+13x-7)=0

We get rid of parentheses

32x^2-52x^2+13x-13x+7-7=0

We add all the numbers together, and all the variables

-20x^2=0

a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-40}=0$

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